| [Q001] What will be the output of the following program
: |
int
main()
{
printf();
return(0);
}
|
(a)Run-Time
Error
(b)Compile-Time Error
(c)No
Output
(d)None of
these |
| Too
few arguments to function 'printf'. |
|
|
| [Q002] What will be the output of the following
program : |
int
main()
{
printf(NULL);
return(0);
}
|
(a)Run-Time Error
(b)Compile-Time
Error
(c)No Output
(d)None of
these |
| Here NULL is treated as a
NULL string. |
|
|
| [Q003] What will be the output of the following
program : |
int
main()
{
printf("%%",7);
return(0);
}
|
(a)7
(b)Compile-Time
Error
(c)%
(d)%% |
| % is a format specifier
and it prints %. The excess arguments are merely ignored i.e. 7. |
|
|
| [Q004] What will be the output of the following
program : |
int
main()
{
printf("//",5);
return(0);
}
|
(a)5
(b)Compile-Time
Error
(c)/
(d)// |
| \ is an escape sequence
but not /. Thus it prints // and the excess arguments are merely
ignored i.e. 5. |
|
|
| [Q005] What will be the output of the following
program : |
int
main()
{
printf("d%",8);
return(0);
}
|
(a)8
(b)Compile-Time
Error
(c)d%
(d)None of
these |
| %d is a format specifier
but not d%. Thus it prints d% and it ignores the excess arguments i.e.
8. |
|
|
| [Q006] What will be the output of the following
program : |
int
main()
{
printf("%d"+0,123);
return(0);
}
|
(a)123
(b)Compile-Time
Error
(c)No Output
(d)None of
these |
| "%d"+0 in the printf
statement has no effect on the output operation.
Thus it prints 123. |
|
|
| [Q007] What will be the output of the following
program : |
int
main()
{
printf("%d"+1,123);
return(0);
}
|
(a)123
(b)Compile-Time
Error
(c)d
(d)No
Output |
| "%d"+1 (or > 0) in the
printf statement affects the program output by considering "%d" as string and ignores
the excess argument i.e. 123. Here 1 refers to the index i.e. 2nd character in the array or string "%d" |
|
|
| [Q008] What will be the output of the following
program : |
int
main()
{
printf("%d",printf("Hi!")+printf("Bye"));
return(0);
}
|
(a)ByeHi!6
(b)Hi!Bye6
(c)Compile-Time
Error
(d)None of these |
| L->R priority and the length of the strings 'Hi!' & 'Bye' is 3+3=6.
The statement printf returns the no. of bytes displayed onto the
screen. |
|
|
| [Q009] What will be the output of the following
program : |
int
main()
{
printf("%d",printf("Hi!")*printf("Bye"));
return(0);
}
|
(a)ByeHi!6
(b)Hi!Bye9
(c)Hi!Bye
(d)None
of these |
| L->R priority and the length of the strings 'Hi!' & 'Bye' is
3*3=9.
The statement printf returns the no. of bytes displayed onto the
screen. |
|
|
| [Q010] What will be the output of the following
program : |
int
main()
{
printf("%d",printf("")+printf(""));
return(0);
}
|
(a)0
(b)No Output
(c)Compile-Time
Error
(d)None of
these |
| L->R priority and the length of the
two strings are 0+0=0.
The statement printf returns the no. of bytes displayed onto the
screen. |
|
|
| [Q011] What will be the output of the following
program : |
int
main()
{
printf("Hi
Friends"+3);
return(0);
}
|
(a)Hi
Friends
(b)Friends
(c)Hi Friends3
(d)None
of these |
| (base adress of
the string 'Hi Friends')+0 points to the value 'H'. Now the NEW (base address)
equals (base address)+3 that points to the character 'F'. Thus it prints the string from 'F' onwards. |
|
|
| [Q012] What will be the output of the following
program : |
int
main()
{
printf("C For ") +
printf("Swimmers");
return(0);
}
|
(a)Compile-Time Error
(b)C For
Swimmers
(c)Run-Time Error
(d)None of
these |
| The value returned by the
printf statements need not be stored or simply ignored. It is a
valid C code. |
|
|
| [Q013] What will be the output of the following
program : |
int
main()
{
printf("\/\*\-*\/");
return(0);
}
|
(a)Run-Time
Error
(b)\/*-*\/
(c)/*-*/
(d)None of
these |
| \ is an escape sequence character. Be careful while analyzing such statements. |
|
|
| [Q014] What will be the output of the following
program : |
int
main()
{
int main=7;
{
printf("%d",main);
return
main;
}
printf("Bye");
return(0);
}
|
(a)Compile-Time
Error
(b)Run-Time
Error
(c)7Bye
(d)7 |
| It is a VALID C code. Prints 7 and returns the same to the
Operating System. NOTE: Last printf statement will not be executed. |
|
|
| [Q015] What will be the output of the following
program : |
int
main()
{
main();
return(0);
}
|
(a)Compile-Time
Error
(b)Executes ONLY once
(c)Infinite
Loop
(d)None of
these |
| main is a function so it
can be called by any other function including itself. Here main is
called by itself and it runs infinite number of times i.e. till the
memory exists. |
|
|
| [Q016] What will be the output of the following
program : |
int
main()
{
printf("Work"
"Hard");
return(0);
}
|
(a)Work
(b)Hard
(c)No
Output
(d)WorkHard |
| It is a valid C code. First it prints the word 'Work'
and then 'Hard'. |
|
|
| [Q017] What will be the output of the following
program : |
int
main()
{
char
str[]="%d";
int val=25;
printf(str,val);
return(0);
}
|
(a)Compile-Time
Error
(b)Run-Time Error
(c)25
(d)None of
these |
| First parameter contains the format specifier & the Second
parameter contains the actual value 25. |
|
|
| [Q018] What will be the output of the following
program : |
int
main()
{
int val=75;
printf("%d",val,.,.);
return(0);
}
|
(a)Compile-Time
Error
(b)No Output
(c)75
(d)None of
these |
| Generates compile-time
error message. Parse error before '.' token. |
|
|
| [Q019] What will be the output of the following
program : |
int
main()
{
int val=10;
printf("%d",val+1,"%d",val--);
return(0);
}
|
(a)10
(b)11
10
(c)11 9
(d)10
9 |
| R->L priority. The second format specifier '%d' is an excess argument and it is
ignored. |
|
|
| [Q020] What will be the output of the following
program : |
int
main()
{
int val=5;
printf("%d %d %d
%d",val,--val,++val,val--);
return(0);
}
|
(a)3 4 6
5
(b)Compiler dependant
(c)4 4 5 5
(d)None of
these |
| The output varies from
compiler to compiler in different platforms. |
|
|
| [Q021] What will be the output of the following
program [NOTE :
ASSUME 2 values are entered by the user are stored in the variables
'val' & 'num' respectively] : |
int
main()
{
int
val=5,num;
printf("%d",scanf("%d
%d",&val,&num));
return(0);
}
|
(a)1
(b)2
(c)5
(d)None
of these |
| It is a valid C code.
scanf statement is embedded inside the printf statement get executed
first. scanf statement returns the number of input fields successfully scanned, converted
and stored. |
|
|
| [Q022] What will be the output of the following
program : |
#define
Compute(x,y,z) (x+y-z)
int
main()
{
int
x=2,y=3,z=4;
printf("%d",Compute(y,z,(-x+y)) *
Compute(z,x,(-y+z)));
return(0);
}
|
(a)40
(b)30
(c)Compile-Time
Error
(d)None of
these |
| During pre-processing the
macro calls are merely replaced by the replacement text. Be careful
while analyzing macro calls. |
|
|
| [Q023] What will be the output of the following
program : |
int
main()
{
int m=10,n=20;
printf("%d %d %d",m/* m-value */,/* n-value */n,m*/* Compute m*n
*/n);
return(0);
}
|
(a)Run-Time
Error
(b)10 20 200
(c)Compile-Time
Error
(d)None of
these |
| Comments /*...*/ are
simply ignored by the compiler. |
|
|
| [Q024] What will be the output of the following
program : |
int
main()
{
int
m=10,n=20;
/*
printf("%d",m*n);
return(0);
}
|
(a)No
Output
(b)Prints 200
(c)Compile-Time
Error
(d)None of
these |
| Unterminated
comment or Comment statement not ended properly i.e */ is missing in the above
C code. |
|
|
| [Q025] What will be the output of the following
program : |
int
main()
{
int val=97;
"Printing..."+printf("%c",val);
return(0);
}
|
(a)Printing...97
(b)97
(c)Compile-Time
Error
(d)a |
| Alphabet 'a' is the ASCII equivalent of 97.
printf statement return the number of bytes displayed onto the
screen and it can be ignored. |
|
|
| [Q026] What will be the output of the following
program : |
int
main()
{
int val=5;
val=printf("C") + printf("Skills");
printf("%d",val);
return(0);
}
|
(a)Skills5
(b)C1
(c)Compile-Time
Error
(d)CSkills7 |
| printf statement return
the number of bytes displayed onto the screen. The length of the
strings 'C' and 'Skills' are 1 + 6 = 7. |
|
|
| [Q027] What will be the output of the following
program : |
int
main()
{
char
str[]="Test";
if ((printf("%s",str)) == 4)
printf("Success");
else
printf("Failure");
return(0);
}
|
(a)TestFailure
(b)TestSuccess
(c)Compile-Time
Error
(d)Test |
| It is valid C code.
printf statement return the number of bytes displayed onto the
screen. |
|
|
| [Q028] What will be the output of the following
program : |
int
main()
{
int val=5;
printf("%*d",val,val);
return(0);
}
|
(a)bbbbb5 (where b means
blankspace)
(b)5
(c)Compile-Time
Error
(d)None of
these |
| Here '*' specifies the precision.
First val is the precision and second val is the actual value. Thus it prints 5 BLANK
SPACES & then the value 5. |
|
|
| [Q029] What will be the output of the following
program : |
int
main()
{
int val=5;
printf("%d5",val);
return(0);
}
|
(a)Compile-Time
Error
(b)5
(c)55
(d)bbbbb5 (where b means
blankspace) |
| %d format specifier is
replaced by the contents of the variable val i.e. 5 followed by
another 5. |
|
|
| [Q030] What will be the output of the following
program : |
int
main()
}
int val=5;
printf("%d",5+val++);
return(0);
{
|
(a)Compile-Time
Error
(b)5
(c)10
(d)11 |
| Incorrect usage of pair of braces } and {.
Correct usage : Each compound statement should be enclosed within a pair of braces, i.e. { and }. |
|
|
|
|
Necessary header files are included
